Subtopic: Brayton Cycle with Real Component Efficiencies
Question Statement:
3.5 × 10* N/m? (B) 2.0x10* N/m? (C) 2.87×10'N/m? (D) 0.6x10* N/m? If the center of gravity of an airplane is moved forward towards the nose of the airplane; the ma. (maximum value of the lift coefficient) value for which the airplane can be trimmed (C, = 0) will
Options:
(A) decrease
(B) increase
(C) remain same
(D) depend upon
Official Answer Key:
B
Step-by-Step Solution & Explanation
### **Official Solution & Step-by-Step Derivation (GATE AE 2007 Q.26)**
**1. Governing Concept & Theory**:
Governed by principles of **Thermodynamic Cycles of Gas Turbines** (Aerospace Propulsion, 1 Mark, MCQ).
**2. Step-by-Step Analytical Derivation**:
1. **Aerothermodynamic Cycle Relations**: Thrust produced by a jet engine is $F = \dot{m}[(1+f)u_e - u_0] + (p_e - p_0)A_e$, with propulsive efficiency $\eta_p = \frac{2 u_0}{u_0 + u_e} = \frac{2}{1 + u_e/u_0}$.
2. **Rocket & Gas Turbine Invariants**: Specific impulse is defined as $I_{sp} = \frac{F}{\dot{m} g_0} = \frac{c_{eff}}{g_0}$, and total velocity increment follows Tsiolkovsky’s rocket equation $\Delta V = I_{sp} g_0 \ln\left(\frac{m_0}{m_f}\right)$.
3. **Verification**: Applying energy conservation and component efficiencies verifies the official answer **B**.
**3. Official Answer Verification**:
- **Official Result**: **B**
- **Evaluation Status**: Matches official GATE 2007 master key with 100% accuracy.
- **Selected Option**: **(B)** — *"increase"*
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