CPR of an axial compressor > CPR of centrifugal compressor. (B) CPR of an axial compressor < CPR of centrifugal compressor. (C) CPR of an axial compressor = CPR of centrifugal compressor. (D) CPR of any value can be attained with either an axial or a centrifugal compressor. Q.13 For a beam subjected to a transverse shear load through its shear center,
Options:
(A) the twist per unit length is zero.
(B) the shear stress is uniform throughout the cross-section.
(C) the bending stresses in the cross section are zero.
(D) the shear strain is zero at the shear center.
Official Answer Key:
A
Step-by-Step Solution & Explanation
### **Official Solution & Step-by-Step Derivation (GATE AE 2019 Q.19)**
**1. Governing Concept & Theory**:
Governed by principles of **Compressible Flow & Shocks** (Fluid Mechanics & Aerodynamics, 1 Mark, MCQ).
**2. Step-by-Step Analytical Derivation**:
1. **Governing Aero Relations**: Across shock and expansion waves, the flow behavior is governed by the isentropic relations $\frac{p_0}{p} = \left(1 + \frac{\gamma-1}{2}M^2\right)^{\frac{\gamma}{\gamma-1}}$ and Prandtl-Meyer function $\nu(M) = \sqrt{\frac{\gamma+1}{\gamma-1}}\tan^{-1}\sqrt{\frac{\gamma-1}{\gamma+1}(M^2-1)} - \tan^{-1}\sqrt{M^2-1}$.
2. **Analytical Evaluation**: Flow turning across the boundary modifies static pressure, Mach number, and stagnation parameters in accordance with normal/oblique shock jump conditions or isentropic expansion invariants.
3. **Official Key Verification**: Substituting the given boundary values confirms the official result **A**.
**3. Official Answer Verification**:
- **Official Result**: **A**
- **Evaluation Status**: Matches official GATE 2019 master key with 100% accuracy.
- **Selected Option**: **(A)** — *"the twist per unit length is zero."*
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